Estimation (Juwana, 2005)
No
|
Component
|
Formula
|
Annotation
|
1
|
Level of occupancy (occ)
|
Occ = Lbruto/Lper-person
You can also count by standard
|
Lbruto = total floor area
Lper-person = 15-20
|
2
|
Envelope / building sensible heat load (BSL)
|
BSL = Lsurface x HL
|
Lsurface = area of bldg element
HL = heat load of bldg component
|
3
|
Internal load:
Sensible and laten of the occupant (OSL, OLL)
Sensible heat load of lamps (LSL)
|
OSL = Occ x 200 BTUh
OLL = Occ x 250 BTUh
LSL = (Σ watt) x 1.25 x 3.4 BTUh
|
|
4
|
Infiltration load (CFM1)
|
CFM1 = (l xw x h x ACH x 35.31) / 60 BTUh
|
|
5
|
Ventilation load
|
CFM2 = (To-Ti) x1.08 + (RHo-RHi) x 0.67 BTUh
|
To = temp outdoor
Ti =indoor
Indonesian case, To-Ti=5oC
RHo = outdoor rel humidity
RH i = Indoor rel humidity
|
6
|
Cooling Load (CL)
|
CL = BSL + OSL + OLL + LSL + CFM1 + CFM 2
|
|
7
|
Cooling Capacity (TR)
|
TR = CL / 12000 BTUh
|
1TR (ton
refrigeration) = 12.000 BTU
1 PK = 9.000 BTU
Cross Check
PK = (A x H)/100 x Koef TR x (12000/900)
Dimana:
PK = Kebutuhan PK AC
A = Luas Ruangan
H = Tinggi Lantai ke Plafond
Koef TR = 1
TUGAS:
* Hitung beban pendinginan dan kebutuhan AC di studi kasus anda
* Gambarkan juga peletakan indoor dan outdoor AC pada denah
Degan asumsi:
To - Ti = 5
Rho - Rhi = 15
Occupancy kelas = 40 orang
Occupancy lab = 15 orang
Occupancy ruang rapat = 20 orang
Degan asumsi:
To - Ti = 5
Rho - Rhi = 15
Occupancy kelas = 40 orang
Occupancy lab = 15 orang
Occupancy ruang rapat = 20 orang
Tugas dikumpulkan pada saat UTS
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