Materi Kuliah Sains Arsitektur, Pencahayaan buatan / electrical lighting

materi kuliah sains arsitektur minggu VII

PERHITUNGAN BEBAN PENDINGINAN

Estimation (Juwana, 2005)

No	Component	Formula	Annotation
1	Level of occupancy (occ)	Occ = Lbruto/Lper-person You can also count by standard	Lbruto = total floor area Lper-person = 15-20
2	Envelope / building sensible heat load (BSL)	BSL = Lsurface x HL	Lsurface = area of bldg element HL = heat load of bldg component
3	Internal load: Sensible and laten of the occupant (OSL, OLL) Sensible heat load of lamps (LSL)	OSL = Occ x 200 BTUh OLL = Occ x 250 BTUh LSL = (Σ watt) x 1.25 x 3.4 BTUh
4	Infiltration load (CFM1)	CFM1 = (l xw x h x ACH x 35.31) / 60 BTUh
5	Ventilation load	CFM2 = (To-Ti) x1.08 + (RHo-RHi) x 0.67 BTUh	To = temp outdoor Ti =indoor Indonesian case, To-Ti=5oC RHo = outdoor rel humidity RH i = Indoor rel humidity
6	Cooling Load (CL)	CL = BSL + OSL + OLL + LSL + CFM1 + CFM 2
7	Cooling Capacity (TR)	TR = CL / 12000 BTUh

1TR (ton refrigeration) = 12.000 BTU

1 PK = 9.000 BTU

Cross Check

PK = (A x H)/100 x Koef TR x (12000/900)

Dimana:

PK           = Kebutuhan PK AC

A             = Luas Ruangan

H             = Tinggi Lantai ke Plafond

Koef TR  = 1

TUGAS:

*  Hitung beban pendinginan dan kebutuhan AC di studi kasus anda

*  Gambarkan juga peletakan indoor dan outdoor AC pada denah

Degan asumsi:
To - Ti = 5
Rho - Rhi = 15
Occupancy kelas = 40 orang
Occupancy lab = 15 orang
Occupancy ruang rapat = 20 orang

Tugas dikumpulkan pada saat UTS

Materi Kuliah Sains Minggu VI